Iterate a list with indexes in Python

yoihj_37141 0
Viewed 328471

I could swear I've seen the function (or method) that takes a list, like this [3, 7, 19] and makes it into iterable list of tuples, like so: [(0,3), (1,7), (2,19)] to use it instead of:

for i in range(len(name_of_list)):
    name_of_list[i] = something

but I can't remember the name and googling "iterate list" gets nothing.

list python
6 Answers
>>> a = [3,4,5,6]
>>> for i, val in enumerate(a):
...     print i, val
...
0 3
1 4
2 5
3 6
>>>
Vinko_Vrsalovic_51900

Yep, that would be the enumerate function! Or more to the point, you need to do:

list(enumerate([3,7,19]))

[(0, 3), (1, 7), (2, 19)]
PierreBdR_71360

Here's another using the zip function.

>>> a = [3, 7, 19]
>>> zip(range(len(a)), a)
[(0, 3), (1, 7), (2, 19)]
SLott_106610
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