Python continue and break usage

Mdick 0
Viewed 41

I need to solve the following problem and I assume I have to use continue and break logic.

  • I have to create an empty to do list and iterate over the dictionary of tasks. I need to add tasks that contain the substring "organize" and once the length of the to do list reaches 2 tasks I break the loop. *
tasks = {
    0 : ['Reorganize the cabinet'],
    1 : ['Give the dog a bath', 'Create a twitter thread'],
    2 : ['Learn python dictionary'],
    3 : ['Take a walk'], 
    4 : ['Go grocery shopping'], 
    5 : ['Update Facebook'],
    6 : ['Respond to emails'],
    7 : ['Walk the dog']
}

I could solve the second part of adding the tasks that contain the substring "organize" and could iterate through the length of tasks to filter tasks that are not more than 2. Yet, I can't find the way how to combine two conditions into one.

continue dictionary python
3 Answers

Put an if statement in the loop that checks the length of the to do list, and breaks out of the loop when it reaches 2.

todo_list = []
for task in tasks.values():
    if any('organize' in item for item in task):
        todo_list.append(task)
    if len(todo_list) == 2:
        break
Barmar0

does this do the job:

to_do_list = []
for value in tasks.values():
    to_do_list.append([val for val in value if 'organize' in val])
    if len(to_do_list) == 2:
        break

If you want a flattened list of items, replace to_do_list.append with to_do_list.extend

anandnpr0

This will work :

to_do_list = []

for task in tasks.values():
    for i in task :
        if 'organize' in i:
            to_do_list.append(i)
    if len(to_do_list) == 2:
        break
ghost21blade0
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