I'm trying to trim out multiple hex words from my string. I'm searching for exactly 3 words, separated by exactly 1 dash each time.
i.e. for this input:
wonder-indexing-service-0.20.0-1605296913-49b045f-19794354.jar
I'd like to get this output:
wonder-indexing-service-0.20.0.jar
I was able to remove the hex words by repeating the pattern. How can I simplify it? Also, I wasn't able to change * to +, to avoid allowing empty words. Any idea how to do that?
What I've got so far:
# Good, but how can I simplify?
% echo 'wonder-indexing-service-0.20.0-1605296913-49b045f-19794354.jar' | sed 's/\-[a-fA-F0-9]*\-[a-fA-F0-9]*\-[a-fA-F0-9]*//g'
druid-indexing-service-0.20.0.jar
# Bad, I'm allowing empty words
% echo 'wonder-indexing-service-0.20.0-1605296913-49b045f-.jar' | sed 's/\-[a-fA-F0-9]*\-[a-fA-F0-9]*\-[a-fA-F0-9]*//g'
druid-indexing-service-0.20.0.jar
Thank you!
EDIT: I had a typo in original output, thank you anubhava for pointing out.