How do you recursively unzip archives in a directory and its subdirectories from the Unix command-line?

If you want to extract the files to the respective folder you can try this

find . -name "*.zip" | while read filename; do unzip -o -d "`dirname "$filename"`" "$filename"; done;

A multi-processed version for systems that can handle high I/O:

find . -name "*.zip" | xargs -P 5 -I fileName sh -c 'unzip -o -d "$(dirname "fileName")/$(basename -s .zip "fileName")" "fileName"'

Here's one solution that extracts all zip files to the working directory and involves the find command and a while loop:

find . -name "*.zip" | while read filename; do unzip -o -d "`basename -s .zip "$filename"`" "$filename"; done;

You could use find along with the -exec flag in a single command line to do the job

find . -name "*.zip" -exec unzip {} \;

Something like gunzip using the -r flag?....

Travel the directory structure recursively. If any of the file names specified on the command line are directories, gzip will descend into the directory and compress all the files it finds there (or decompress them in the case of gunzip ).

http://www.computerhope.com/unix/gzip.htm

If you're using cygwin, the syntax is slightly different for the basename command.

find . -name "*.zip" | while read filename; do unzip -o -d "`basename "$filename" .zip`" "$filename"; done;

this works for me

def unzip(zip_file, path_to_extract):
    """
    Decompress zip archives recursively
    Args:
        zip_file: name of zip archive
        path_to_extract: folder where the files will be extracted
    """
    try:
        if is_zipfile(zip_file):
            parent_file = ZipFile(zip_file)
            parent_file.extractall(path_to_extract)
            for file_inside in parent_file.namelist():
                if is_zipfile(os.path.join(os.getcwd(),file_inside)):
                    unzip(file_inside,path_to_extract)
            os.remove(f"{zip_file}")
    except Exception as e:
        print(e)