How do I split a string, breaking at a particular character?

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I have this string

'john smith~123 Street~Apt 4~New York~NY~12345'

Using JavaScript, what is the fastest way to parse this into

var name = "john smith";
var street= "123 Street";
//etc...
17 Answers

With JavaScript’s String.prototype.split function:

var input = 'john smith~123 Street~Apt 4~New York~NY~12345';

var fields = input.split('~');

var name = fields[0];
var street = fields[1];
// etc.

You don't need jQuery.

var s = 'john smith~123 Street~Apt 4~New York~NY~12345';
var fields = s.split(/~/);
var name = fields[0];
var street = fields[1];

You'll want to look into JavaScript's substr or split, as this is not really a task suited for jQuery.

well, easiest way would be something like:

var address = theEncodedString.split(/~/)
var name = address[0], street = address[1]

split() method in JavaScript is used to convert a string to an array. It takes one optional argument, as a character, on which to split. In your case (~).

If splitOn is skipped, it will simply put string as it is on 0th position of an array.

If splitOn is just a “”, then it will convert array of single characters.

So in your case:

var arr = input.split('~');

will get the name at arr[0] and the street at arr[1].

You can read for a more detailed explanation at Split on in JavaScript

Something like:

var divided = str.split("/~/");
var name=divided[0];
var street = divided[1];

Is probably going to be easiest

This string.split("~")[0]; gets things done.

source: String.prototype.split()


Another functional approach using curry and function composition.

So the first thing would be the split function. We want to make this "john smith~123 Street~Apt 4~New York~NY~12345" into this ["john smith", "123 Street", "Apt 4", "New York", "NY", "12345"]

const split = (separator) => (text) => text.split(separator);
const splitByTilde = split('~');

So now we can use our specialized splitByTilde function. Example:

splitByTilde("john smith~123 Street~Apt 4~New York~NY~12345") // ["john smith", "123 Street", "Apt 4", "New York", "NY", "12345"]

To get the first element we can use the list[0] operator. Let's build a first function:

const first = (list) => list[0];

The algorithm is: split by the colon and then get the first element of the given list. So we can compose those functions to build our final getName function. Building a compose function with reduce:

const compose = (...fns) => (value) => fns.reduceRight((acc, fn) => fn(acc), value);

And now using it to compose splitByTilde and first functions.

const getName = compose(first, splitByTilde);

let string = 'john smith~123 Street~Apt 4~New York~NY~12345';
getName(string); // "john smith"

Try in Plain Javascript

 //basic url=http://localhost:58227/ExternalApproval.html?Status=1

 var ar= [url,statu] = window.location.href.split("=");

JavaScript: Convert String to Array JavaScript Split

    var str = "This-javascript-tutorial-string-split-method-examples-tutsmake."
 
    var result = str.split('-'); 
     
    console.log(result);
     
    document.getElementById("show").innerHTML = result; 
<html>
<head>
<title>How do you split a string, breaking at a particular character in javascript?</title>
</head>
<body>
 
<p id="show"></p> 
 
</body>
</html>

https://www.tutsmake.com/javascript-convert-string-to-array-javascript/

Since the splitting on commas question is duplicated to this question, adding this here.

If you want to split on a character and also handle extra whitespace that might follow that character, which often happens with commas, you can use replace then split, like this:

var items = string.replace(/,\s+/, ",").split(',')

This isn't as good as the destructuring answer, but seeing as this question was asked 12 years ago, I decided to give it an answer that also would have worked 12 years ago.

function Record(s) {
    var keys = ["name", "address", "address2", "city", "state", "zip"], values = s.split("~"), i
    for (i = 0; i<keys.length; i++) {
        this[keys[i]] = values[i]
    }
}

var record = new Record('john smith~123 Street~Apt 4~New York~NY~12345')

record.name // contains john smith
record.address // contains 123 Street
record.address2 // contains Apt 4
record.city // contains New York
record.state // contains NY
record.zip // contains zip
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