How can i filter fancy texts in python

Farhang 0
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I have a simple script in python copy text and paste another place i wanna Prevent Copy if a text have fancy character like bottom

Ｈｅｌｌｏ ℌ

Must Skip Emojies and legal characters (Arabic & English)

How can it possible as easiest way

python
2 Answers

with the built in string function .isascii(), if the string contains anything that is not ascii, it will return false, example:

# if text is ascii or is arabic or is imojie print True else print false

text = 'هلا hala'
print(all((ord(c) < 128709 and ord(c) > 127568) or (ord(c) < 1609 and ord(c) > 1568) or c.isascii() for c in text)) # True

text = ' موز '
print(all((ord(c) < 128709 and ord(c) > 127568) or (ord(c) < 1609 and ord(c) > 1568) or c.isascii() for c in text)) # True

text = ''
print(all((ord(c) < 128709 and ord(c) > 127568) or (ord(c) < 1609 and ord(c) > 1568 ) or c.isascii() for c in text)) # True

text = 'love '
print(all((ord(c) < 128709 and ord(c) > 127568) or (ord(c) < 1609 and ord(c) > 1568 ) or c.isascii() for c in text)) # True

text = 'banana'
print(all((ord(c) < 128709 and ord(c) > 127568) or (ord(c) < 1609 and ord(c) > 1568 ) or c.isascii() for c in text)) # True

text = 'Ｈｅｌｌｏ ℌ '
print(all((ord(c) < 128709 and ord(c) > 127568) or (ord(c) < 1609 and ord(c) > 1568 ) or c.isascii() for c in text)) # False
Hannon qaoud0

I'll explore this a bit before giving a solution. Firstly lets look into the ASCII for normal alphabets

ord("A"), ord("Z"), ord("a"), ord("z")
    
(65, 90, 97, 122)

The ASCII numbers between 90 and 97 are for brackets, or other such instances if i'm not wrong.

Coming to fancy text, this is what I found.

ord("ᴇ")
    
7431

Hence I think its safe to say that if your string has an ASCII outside the range from before, then its probably styled, and you can put a condition to skip it.

Gautam Chettiar0
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