Why do I get a None output when I use this if statement

Grak 0
Viewed 28
 Alph= ["a","A","b","B","c","C","D","d","e","E","f","F","g","G","h","H","i","I","j","J","k","K","l","L","m","M","n","N","o","O","p","P","q","Q","r","R","s","S","t","T","u","U","v","V","w","W","x","X","y","Y","z","Z"]
Num = [1,2,3,4,5,6,7,8,9,0]

  D1 = random.randint(1,6)
  D2 = random.randint(1,6)   
  P1_S = 0  
        P1_MS = input("Type a letter to begin player 1 and roll dice")
    if P1_MS == Alph or Num:
                 P1_S = P1_S + D1 + D2, print("First roll is", D1), print("Second roll is", D2)
                 print(P1_S, "is the total amount")

After this I appear to get the "none, none" part so how can I remove that from my output? Output:

First roll is 3
Second roll is 3
(6, None, None) is the total amount

How can I remove the None, None at the end of the output?

nonetype output printing python
3 Answers

It's because of this line:

P1_S =P1_S+D1+D2 , print("First roll is", D1) , print("Second roll is", D2)

The commas mean you're assigning P1_S to be a three-element tuple. The first element is P1_S+D1+D2, the second element is the result of a print() function (which always returns None), and the third element is another print.

So, you end up with (6, None, None) as the value.

John Gordon0

You haven't mentioned what is P1_S in your code, or where you have declared it. I guess you have made it a list or some other datatype than simple Int. Check it.

Priyankar Koley0

Please give more code (in the snippet P1_S is not defined)

If you want to learn: Try it with a new .py file, only for the stack overflow question.

If you only want an answer, try this, and give feedback:

P1_S =int(P1_S)+int(D1)+int(D2)
print("First roll is", int(D1))
print("Second roll is", int(D2))
print (str(P1_S[0]),"is the total amount")

The important part for you is in the last line P1_S[0] access the first entry ("6") which should be your result as I understand.

mcgrow0
Related