Iterate over find command's output with exec or xargs & pass this as paramater to script

usert4jju7 0
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I have to find files & execute a python command on them. There are several thousand files that find command finds. So, instead of running a for loop to iterate over the output of find command, I'm trying to do an xargs over find output.

I am unable to work out how to pass the output of find command as parameter to the script.

find "$DIRLOC" -iname "*.html" |
xargs python3 src/shell/updates/python/updateshere.py <filename from find command's output to go here> "$HASH" {} \;

Please could someone help me with this?

xargs exec bash
1 Answers

You can do it like this:

find "$DIRLOC" -iname "*.html" -print0 |
xargs -0 -I {} python3 src/shell/updates/python/updateshere.py {} "$HASH"

Used -print0 option in find and -0 in xargs to handle filename/directory names with space or other special characters.

You can handle all in find also using -exec option:

find "$DIRLOC" -iname "*.html" -exec \
python3 src/shell/updates/python/updateshere.py {} "$HASH" \;
anubhava0
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