Python create instance attributes by kwargs

kwargs is a dictionary and you can set class attributes from a dictionary using self.__dict__:

class Test:
    def __init__(self, **kwargs):
        self.__dict__.update(kwargs)

t = Test(a=1, b=2, c=3)
print(t.a, t.b, t.c)

Output:

1 2 3

Using self.__setattr__():

class Test:
    def __init__(self, *args, **kwargs):
        for key, val in kwargs.items():
            self.__setattr__(key, val)


t = Test(a=1, b=2, c=3)

print(t.a, t.b, t.c)
# 1 2 3

Iterate over kwargs and set attributes by calling setattr():

class MyClass:
    def __init__(self, *args, **kwargs):
        """Create instance attributes from dict"""
        for key, value in kwargs.items():
            setattr(self, key, value)
    

t = Test(a=1, b=2, c=3)

print(t.a, t.b, t.c)

Check here for more details about setattr() method in Python.

Check here for more details about Python **kwargs.

The setattr function is the friend you're looking for:

class Test:
    def __init__(self, *args, **kwargs):
        for k, v in kwargs.items():
            self.__setattr__(k, v)

t = Test(1, b=2, c=3)

print(t.a, t.b, t.c)

Result:

1 2 3

In more complex code, you might not want to assign all of the key/value pairs in **kwargs as instance attributes, and you might want to be sure that the caller provides some required values. You could make the params explicit and still get the behavior you want, with something like:

class Test:
    def __init__(self, a, b, *args, **kwargs):
        self.__setattr__('a', a)
        self.__setattr__('b', b)
        if 'c' in kwargs:
            self.__setattr__('c', kwargs['c'])

t = Test(1, 2, c=3)

print(t.a, t.b, t.c)

Same result:

1 2 3

I'll fill in what you're missing here:

class Test:

    def __init__(self, *args, **kwargs):
    """Create instance attributes from dict"""
        self.a = kwargs["a"]
        self.b = kwargs["b"]
        self.c = kwargs["c"]

t = Test(a=1, b=2, c=3)
print(t.a, t.b, t.c)