I have a text file with many lines of numbers and wish to find the highest number. I have already found the average of all the numbers.
Here is my code so far:
file = open('max_vind_sola_enkelttall.txt', 'r')
lines = file.read
sum = 0
for lines in file:
sum += float(lines)
amount = 362
average = sum/amount
print("average is: ", average)
file.close()
Dealing with min and max are very similar to dealing with accumulating the sum/total.
with open('max_vind_sola_enkelttall.txt') as file:
total = 0
count = 0
mn = float('inf')
mx = float('-inf')
for line in file:
count += 1
v = float(line)
total += v
if v < mn:
mn = v
if v > mx:
mx = v
average = total / count
print("average is: ", average)
print("max is: ", mx)
print("min is: ", mn)
Note that I used a with clause to make sure that the file gets closed properly no matter what else happens. These days, we should seldom be calling close() on a stream explicitly, especially when reading and writing local files like this.
file = open('max_vind_sola_enkelttall.txt', 'r')
lines = file.read
sum = 0
max = 0
for lines in file:
sum += float(lines)
if float(lines) > max:
max = lines
amount = 362
average = sum / amount
print("average is: ", average)
print("max is: ", max)
If your numbers are a list of floats, you can use the max function with your list as the input.
ex.
file = open('max_vind_sola_enkelttall.txt', 'r')
lines = file.readlines()
lines = [float(x) for x in lines]
largest_float = max(lines)
print(largest_float)