reverse_lazy not redirecting to the correct link (adding a suffix)

Ayat Rahman 0
Viewed 25

so this is my class based function

class AddCommentView(CreateView):
model = Comment

form_class = CommentForm
template_name = 'app/add_comment.html'
def form_valid(self, form):
list_obj = List.objects.get(slug = self.kwargs['slug'])
        form.instance.list = list_obj
return super().form_valid(form)

success_url = reverse_lazy("app:list_detail", kwargs={'slug': List.slug})

once the comment is submitted I wanna go back to detailview page which is

http://127.0.0.1:8000/home/list/best-bangla-art-films2022-09-09-0505595309260000/

but its taking me to

http://127.0.0.1:8000/home/list/best-bangla-art-films2022-09-09-0505595309260000/comment/

any way i can solve this?

in my urls

(I have excluded irrelevant paths)

app_name = "app"
urlpatterns = [
path('', views.HomeView.as_view(),name='home'),
path('list/<slug:slug>/', TheirDetailView.as_view(),name='list_detail'),
path('list/<slug:slug>/comment/',AddCommentView.as_view(),name="add_comment"),
]
django-urls slug django-views django
1 Answers

Try to change success_url = reverse_lazy("app:list_detail", kwargs={'slug': List.slug}) to success_url = reverse_lazy("app:list_detail", kwargs={'slug': list_obj.slug}). You should use the variable name, not the Model

Giorgio Scarso0
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