Write a recursive function, mult5, that will return how many numbers in the list are
multiples of 5.
(mult5 ‘(60 22 13 25) ===> 2 (mult5 ‘(5) ===> 1 (mult5 ‘() ===> 0
(define (mult5 ls) (if (null? ls) '() (cons ( * car (ls) car(ls)) ( mult5 cdr (ls) cdr (ls)))))