I have a cell with dimension 41X41 as shown below
that has values equal to 1, it means all its values are equal to ones as shown below:
Based on many values, I could not include it here in one figure, but its dimension is 41 x 41.
What I was trying to do is calculate the number of ones in each row minus one as shown in the snippet of line code below:
ccc = sum(isSmaller{cc,:} == 1)-1
In order to get a cell with 1 row with 40 columns dimension that has 40s. as shown below:
My problem is instead of 40 columns is still showing 41 columns after deleting one from each row as indicated below.
May I get assistance, please? I need it to be 1 row with 40 columns.
Note: I do not care for the first 40 rows or columns or the lasts or the middle ones. I just need it to be done by itself only by minus one.
After that, I need to sum all the 40s in this ccc = 1x40.
Below is my try:
for cc = 1:length(isSmaller)
ccc = sum(isSmaller{cc,:} == 1)-1
end



