function with while loop python with two different result

user_19601668 0
Viewed 44

I want to code a function and get expected results like this (when i input number = 10):

10
9
8
7
6
5
4
3
2
1

And when i input number = -10 :

-10
-9
-8
-7
-6
-5
-4
-3
-2
-1

This is my code. Only works when number = 10. No result when im trying to input a = -10:

def function_while(number):
i=0
while i<number:     
    if True:
        print(number-i)
    else:
        print(number+1)
    i+=1
function_while(number)

Is there any solution?

if-statement while-loop function python loops
3 Answers

I would suggest a for-loop over a while loop since you know the number of iterations needed:

def f(n):
    sign = -1 if n < 0 else 1
    for i in reversed(range(1, abs(n)+1)):
        print(i*sign)

But, if you're set on the while loop:

def function_while(x):
    sign = -1 if x < 0 else 1
    number = abs(x)
    i=0
    while i<number:     
        print((number-i)*sign)
        i+=1

The trick is to use a variable, sign which is -1 if the input is negative, otherwise 1.

user_139567300

Be pythonic, use a simple range:

def f(number):
    for i in range(number, 0, -1 if number>0 else 1):
        print(i)

Example:

f(5)
5
4
3
2
1

f(-5)
-5
-4
-3
-2
-1
user_163434640 
def func(num):
    step = -1 if num > 0 else 1
    while num != 0:
        print(num)
        num += step
user_28814630
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