shape file and sf data-frame geometry into latitude longitude columns

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I have a simple shape file with multipolygons .shp file data

read data into R

shp <- st_read("/home/rdfleay/Desktop/R/WestAustralia/GeographeBay/data/gb_gensub50a.shp") # sf()

attempt projection, wanting lat lon, but data remains in meters..

shp_t <- st_transform(shp, crs = st_crs(shp))

project using 'standard' to get lat-lon

shp_4326 = st_transform(shp, "EPSG:4326") #

i am trying to get the geometry as columns of 'lat' & 'lon'

reef_GBay <- shp_4326 %>% 
   filter(Substrate == "Reef")

nrow(reef_GBay)

t(reef_GBay)

print(reef_GBay$geometry)

head(reef_GBay$geometry)

as.data.frame(reef_GBay)
head(reef_GBay$geometry)

so far the output remains a single row?? thanks for the help

sp sf latitude-longitude r
1 Answers

Use st_coordinates() to get the matrix of coordinates and coerce it to data frame:

url <- "https://data.imas.utas.edu.au/attachments/275f62b0-0b6c-4514-90c7-deeae423ab23/MarineFutures_GeographeBay_reef.zip"
f <- "file.zip"
download.file(url, f, mode = "wb")

unzip(f, exdir = "junk", junkpaths = TRUE)

library(sf)

shp <- st_read("junk/gb_gensub50a.shp")
#> Reading layer `gb_gensub50a' from data source 
#> Simple feature collection with 4 features and 2 fields
#> Geometry type: MULTIPOLYGON
#> Dimension:     XY
#> Bounding box:  xmin: 321407.5 ymin: 6279315 xmax: 339012.5 ymax: 6289742
#> Projected CRS: GDA94 / MGA zone 50


# To get lon/lat

library(dplyr)

df <- shp %>%
  # 1. Project to lon/lat
  st_transform(4326) %>%
  # Your filter
  filter(Substrate == "Reef") %>%
  # 2 Extract coordinates
  st_coordinates() %>%
  # 3 to table /tibble
  as.data.frame()

head(df)
#>          X         Y L1 L2 L3
#> 1 115.1362 -33.59926  1  1  1
#> 2 115.1362 -33.59937  1  1  1
#> 3 115.1361 -33.59946  1  1  1
#> 4 115.1361 -33.59946  1  1  1
#> 5 115.1361 -33.59946  1  1  1
#> 6 115.1361 -33.59949  1  1  1

Created on 2022-06-16 by the reprex package (v2.0.1)

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