Rename part of the directory names?

user_825920 0
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The following command found the following directories.

$ find tmp/ -name "date=*" -type d
tmp/year=2022/month=05/date=27
tmp/year=2022/month=05/date=21
tmp/year=2022/month=05/date=29
tmp/year=2022/month=05/date=24
tmp/year=2022/month=05/date=31
tmp/year=2022/month=06/date=01
tmp/year=2022/month=06/date=02

I need to rename the directories by replacing date= to day=.

find tmp/ -name "date=*" -type d -exec rename s/date=/day=/g "{}" +;

However, the command doesn't rename the directories?

I will need to implement it in Python.

python bash
3 Answers

rename utility is not part of standard Unix tool/utilities and comes in different flavors.

I may suggest sticking with bash and mv using this find command:

find tmp -name "date=*" -type d -exec bash -c '
   for f;do echo mv "$f" "${f/date=/day=}"; done' _ {} +

I have kept echo before mv for your testing purpose. Once satisfied with the output just remove echo from above command.

user_5482250

If you want to do this from Python anyway, a subprocess is just unnecessary.

import os

for curdir, dirs, files in os.walk("/tmp"):
    for dirname in dirs:
        if dirname.startswith("date="):
            new = dirname.replace("date=", "day=")
            os.rename(os.path.join(curdir, dirname), os.path.join(curdir, new))
user_8741880

If you are on Python 3.4+, you can use pathlib:

from pathlib import Path

tmp = Path('tmp')

for o in tmp.rglob('date=*'):
    if o.is_dir():
        o.rename(o.with_name(o.name.replace('date', 'day')))

To address the problem you mentioned in your post comment, you can check if the target directory already exists and then workaround it the way you want. Something like this:

from pathlib import Path

tmp = Path('tmp')

for o in tmp.rglob('date=*'):
    new_name = o.with_name(o.name.replace('date', 'day'))
    if o.is_dir():
        if new_name.exists():
            # Your logic to work around a directory
            # that already exists goes here
        else:
            o.rename(new_name)

The code above is just an initial idea. It needs a lot of improvement to be made more reliable.

user_67893210
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