Convert jQuery ready function to TypeScript

user_9971404 0
Viewed 26

I'm trying to replace some old code that uses jQuery, to the new way without it.

The old code, using the ready function:

function myFunc() { }

$(function() {
  myFunc();
});

I found this equivalent at "You Might Not Need jQuery":

function myFunc() { }

function ready(fn) {
  if (document.readyState != 'loading')
    fn();
  else
    document.addEventListener('DOMContentLoaded', fn);
}
ready(myFunc);

I'm using TypeScript, so it complains about fn being implicit any. I'd like to avoid that.

I tried: fn: Function, but the compiler complains about the overloads to addEventListener, and I'm unsure how to handle it.

How do I avoid any?

typescript jquery
1 Answers
function myFunc() { }

function ready(fn:() => void) {
  if (document.readyState != 'loading')
    fn();
  else
    document.addEventListener('DOMContentLoaded', fn);
}
ready(myFunc);

You can type it like this.

user_158324310
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