How to exit out of While loop is condition meet

user_18154281 0
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I have a infinite loop need to exit the script if condition meets and print my expected output

Code:

import random

stud=[0,0]
studnme = ['a','b']

while (stud[0] !=50 or stud[1] !=50):
    if flag = 0:
        lucky_draw = random.randint(1,6)
        stud_marks = stud[0] + lucky_draw
        stud[0]    = stud[0] + lucky_draw  
        flag=1 
    else:
        lucky_draw = random.randint(1,6)
        stud_marks = stud[1] + lucky_draw
        stud[0]    = stud[1] + lucky_draw  
        flag=0

Output :

Student 'a' You have reached : 50
Student 'b' You have reached : 34

Need to print who as highest points

python
2 Answers

The values you're testing to exit the loop are incremented by random values, so they're not guaranteed to hit 50 exactly. Make the loop run while those values are less than 50.

while (stud[0] < 50 and stud[1] < 50):
Bill_the_Lizard_12880 

import random

stud=[0,0]
studnme = ['a','b']
flag=0
while (stud[0] <=50 or stud[1] <=50):
    if flag == 0:
        lucky_draw = random.randint(1,6)
        stud_marks = stud[0] + lucky_draw
        stud[0]    = stud[0] + lucky_draw  
        flag=1 
    else:
        lucky_draw = random.randint(1,6)
        stud_marks = stud[1] + lucky_draw
        stud[1]    = stud[1] + lucky_draw  
        flag=0      
print(f'Student a you have reached :{stud[0]}')
print(f'Student b you have reached :{stud[1]}')

First of all you have not defined the flag, so set it to 0 or 1 and also the condition that you have kept should be a little changed , that is as any of the student has marks greater than 50 the program should terminate. Please check the above code.

user_154400610
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