Print every possible 2-letter combination from a string containing 3 letters in python

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The below code currently produces only 3 letter combinations from the 3-letter string. How can I revise the code to produce every 2-letter combination and add "2022" to every combination (such as CE2022, CO2022, OC2022, EO2022, etc.)?

d='CEO'
t=list(itertools.permutations(d,len(d)))
for i in range(0,len(t)):
    print(''.join(t[i]))

Output:
CEO
COE
ECO
EOC
OCE
OEC
combinations permutation python-3.x string
2 Answers

If you change len(d) to 2 you get every 2-letter combination:

d='CEO'
t=list(itertools.permutations(d,2))
for i in range(0,len(t)):
    print(''.join(t[i])+'2022')

Output:

CE2022
CO2022
EC2022
EO2022
OC2022
OE2022

You can also make this more Pythonic:

import itertools
d='CEO'
t=itertools.permutations(d,2)
for i in t:
    print(''.join(i)+'2022')
user_154566810

Same as the other answer but using a list comprehension:

import itertools

d = 'CEO'

result = ["".join(i) + "2022" for i in itertools.permutations(d, 2)]

print(result)
user_121892570
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