I have the following string
huile contains rgbgrbrb9gr && huile contains fcecec
I use this regex in order to capture a block of condition:
(.+) (contains) (.+)
It works with one block "huile contains rgbgrrb9gr" but if i add another condition with && or || operator, the two operators are captured. What i'm expecting to capture if the two blocks excluding && and || operator.
Can someone have any idea how to achieve this?
Regex normally matches the longest input it finds.
You need to exclude & and | from your input, like this:
([^&|]+) (contains) ([^&|]+)
If you instead desire to exclude double-character && and ||, I suggest spliting your string based on those delimiters first, then matching using regex, as complex parsing is really beyond the realm of regex (they're grammars actually).
But, a regex solution is nontheless possible
The rough idea is that, you want to match a string with
& or |& or | followed by a non-empting stringthe subpattern would be something like this:
(([^&|]+)?([&|][^&|]+)+)
additionally, you'll want something like the egrep's x flag, to match the entire string, otherwise it'll be possible that an empty string turns up.
The full regex would look something like this (capture groups're re-numbered)
(([^&|]+)?([&|][^&|]+)+) (contains) (([^&|]+)?([&|][^&|]+)+)
After reading the post comments, the desired result was more clear.
This one could work too:
(?<=^|(?:&&|\|\|) )(.+?) (contains) (.+?)(?= (?:&&|\|\|)|$)
If you want 3 capture groups, you could match what you don't want first, and then capture in groups what you want to keep making use of a tempered greedy token approach to not cross matching && or || or the word contains.
\|{2,}|&{2,}|((?:(?!&&|\|\||\bcontains\b).)*) (contains) ((?:(?!&&|\|\||\bcontains\b).)*)
The pattern matches:
\|{2,}|&{2,} Match either 2 or more pipe chars or ampersands (what you don't want to keep)| Or( Capture group 1
(?:(?!&&|\|\||\bcontains\b).)* Match any char except a newline if what is directly to the right is not && || or contains) Close group 1 (contains) Match the word contains in group 2 between spaces( Capture group 3
(?:(?!&&|\|\||\bcontains\b).)* Same approach as above) Close group 3