How can I delete a docker images by their tag <none> and repository name?

user_4759182 0
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I would like to ask if it's possible to delete docker images for its tag or the created label, I have something like this:

Repository                     TAG             IMAGE_ID       CREATED          SIZE

registry.someRegistry.         latest          fa8767676       5 hours ago     119MB
registry.someRegistry.         <none>          878787874       29 hours ago    119MB
registry.someRegistry.         <none>          jkj7jjjk4       2 days ago      119MB
registry.someRegistry.         <none>          d99090iii       3 days ago      119MB

I need to remove all the images but not the most recently one in this case is the one tagged with latest or the one with the most recent Created date. I can use the next command to delete all the images until 5 hours of creation, but it's not appropriate, because I could delete more images not just the last one, would be better to delete images by the tag=latest.

docker image prune -a --force --filter "until=5h"

I need also an additional filter for the registry I think, in order to remove just the images for the registry I need.

Any good way to achieve that?

docker
3 Answers

The simplest would be the rmi command, i.e.:

docker rmi 878787874

This is a "remove image" command and uses the IMAGE_ID you list.

user_29339770

None of the replies were helpful, and there does not seem to be another thread either. It is way too late but I had the same problem and found this solution:

docker rmi $(docker images | grep "<none>" | grep "registry.someRegistry." | awk {'print $3'})

This is not 100% proof because grep looks for a string in the name and the tag, so theoretically if your registry name appears in some tag and vice versa you could accidentally delete it.

user_164954950

you can remove dangling images with filter

 docker images --filter dangling=true
user_13453030
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