What is the difference between these two? Why do they have different outputs? Thanks!
(66.2-65)/(4.2/8) %>%
pt(63)
((66.2-65)/(4.2/8)) %>%
pt(63)
What is the difference between these two lines of codes?
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1 Answers
In the first case (4.2/8) %>% pt(63) happens first. Let
a <- (66.2-65)
b <- (4.2/8)
Case 1
(66.2-65)/(4.2/8) %>% pt(63)
[1] 1,716034
a/pt(b,63)
[1] 1,716034
Case 2
((66.2-65)/(4.2/8)) %>% pt(63)
[1] 0,987177
pt(a/b,63)
[1] 0,987177
So, we have a/pt(b,63) x pt(a/b,63)
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