Don't Understand Concept

user_16239981 0
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Given the below array, create a function which loops through each name, comparing the length of each to determine the longest name, save that name to the variable longest_name. Return longest_name to the another variable called answer and log the answer variable to the screen.

let array = [ "John", "Lee", "Smitty", "Cyren", "Linda", "Bart", "Jason", "Wilson", "Travis", "Newt"];

would it be something like this

let array = [ "John", "Lee", "Smitty", "Cyren", "Linda", "Bart", "Jason", "Wilson", "Travis", "Newt"];

let result = array.filter(val =>includes(val));

console.log(result);

string-length compare function arrays javascript
2 Answers

Here is a sample implementation.

// A function which accepts an array as input
function findLongest(names) {
  let longest_name = '';
  // Loop through all the names
  for (let i = 0; i < names.length; i += 1) {
    // If the names is longer than longest_name, update it
    if (names[i].length > longest_name.length) {
      longest_name = names[i];
    }
  }
  return longest_name;
}

let array = [ "John", "Lee", "Smitty", "Cyren", "Linda", "Bart", "Jason", "Wilson", "Travis", "Newt"];

let answer = findLongest(array);

console.log(answer)

user_162311080

Simply use reduce on the array and return the longest element every time.

The longest variable will contain the last longest element.

Do run the snippet and understand how reduce, ? : (Elvis operator) works in javascript

let array = [ "John", "Lee", "Smitty", "Cyren", "Linda", "Bart", "Jason", "Wilson", "Travis", "Newt"];
let longest = array.reduce((prev, curr) => curr.length > prev.length ? curr : prev,'');
console.log(longest)

Hope this helps

user_108743280
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