BigDecimal. multiply() and divide() methods return hexadecimal number. Why?

user_15792341 0
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Here is my code: 

public class Test1 {
    public static void main(String[] args) {
        BigDecimal wallet = new BigDecimal("0.0");
        BigDecimal productPrice = new BigDecimal("0.01");

        for (int i = 1; i <= 5; i++) {
            wallet = wallet.multiply(productPrice);
        }
        System.out.println(wallet);
    }
}

Result: 0E-11
I have a question. Why am I getting the result in the hexadecimal number system and not in decimal? Like this: 2.45

bigdecimal java
2 Answers

That's not a hexadecimal, it's the scientific notation as evaluated by the toString() method:

Returns the string representation of this BigDecimal, using scientific notation if an exponent is needed.

The E letter denotes the exponent of the number.

In general if you want to format a decimal number, you can use java.text.DecimalFormat.

user_10642450

In your case, the method toString is used which will use an exponent field if needed.

You can use toPlainString if you do not want a string representation with an exponent field.

System.out.println(wallet.toPlainString());
user_2433730
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