filter or delete some dictionaries in a json file

See simple function at the beginning of following code, this function filters (removes) error entries. Usage of this function at the end of code.

Try it online!

def Filter(data):
    return [e for e in data if "error" not in e]


data = [
    {
        "id": 1,
        "jsonrpc": "2.0",
        "result": {
            "account": "booster",
            "follower_count": 16055,
            "following_count": 15,
        },
    },
    {
        "id": 1,
        "jsonrpc": "2.0",
        "result": {
            "account": "bot-helper",
            "follower_count": 4286,
            "following_count": 5490,
        },
    },
    {
        "id": 1,
        "jsonrpc": "2.0",
        "result": {
            "account": "cheetah",
            "follower_count": 20296,
            "following_count": 1,
        },
    },
    {
        "id": 1,
        "jsonrpc": "2.0",
        "result": {
            "account": "cleverbot",
            "follower_count": 3566,
            "following_count": 1446,
        },
    },
    {
        "id": 1,
        "jsonrpc": "2.0",
        "result": {
            "account": "discordia",
            "follower_count": 2283,
            "following_count": 13,
        },
    },
    {
        "error": {
            "code": -32602,
            "data": "invalid account char",
            "message": "Invalid parameters",
        },
        "id": 1,
        "jsonrpc": "2.0",
    },
    {
        "error": {
            "code": -32602,
            "data": "invalid account char",
            "message": "Invalid parameters",
        },
        "id": 1,
        "jsonrpc": "2.0",
    },
    {
        "error": {
            "code": -32602,
            "data": "invalid account char",
            "message": "Invalid parameters",
        },
        "id": 1,
        "jsonrpc": "2.0",
    },
]

print(Filter(data))

Output:

[
    {
        "id": 1,
        "jsonrpc": "2.0",
        "result": {
            "account": "booster",
            "follower_count": 16055,
            "following_count": 15,
        },
    },
    {
        "id": 1,
        "jsonrpc": "2.0",
        "result": {
            "account": "bot-helper",
            "follower_count": 4286,
            "following_count": 5490,
        },
    },
    {
        "id": 1,
        "jsonrpc": "2.0",
        "result": {
            "account": "cheetah",
            "follower_count": 20296,
            "following_count": 1,
        },
    },
    {
        "id": 1,
        "jsonrpc": "2.0",
        "result": {
            "account": "cleverbot",
            "follower_count": 3566,
            "following_count": 1446,
        },
    },
    {
        "id": 1,
        "jsonrpc": "2.0",
        "result": {
            "account": "discordia",
            "follower_count": 2283,
            "following_count": 13,
        },
    },
]

Filter is a built in function in python. Here is some docs explaining usage.

This should work for your case:

data = [{'id': 1, 'jsonrpc': '2.0'... # Complete this line with your data
filtered_data = filter(lambda x: 'error' not in x, data)
print(filtered_data) # <filter object at 0x10aa164c0>

filter returns a filter object to lazy-load data and conserve memory. It's best to iterate using a for-loop, but you can cast to a list to reveal the results (this uses more memory).

filtered_data = list(filtered_data)
print(filtered_data) # [{'id': 1, 'jsonrpc': '2.0'...

This is written assuming that you only want to filter out that very particular dictionary content, not all error entries.

Just use a list comprehension and remove unwanted dictionaries.

li1 =  [{'id': 1,
    'jsonrpc': '2.0',
    'result': {'account': 'booster',
    'follower_count': 16055,
    'following_count': 15}},
    {'id': 1,
    'jsonrpc': '2.0',
    'result': {'account': 'bot-helper',
    'follower_count': 4286,
    'following_count': 5490}},
    {'id': 1,
    'jsonrpc': '2.0',
    'result': {'account': 'cheetah',
    'follower_count': 20296,
    'following_count': 1}},
    {'id': 1,
    'jsonrpc': '2.0',
    'result': {'account': 'cleverbot',
    'follower_count': 3566,
    'following_count': 1446}},
    {'id': 1,
    'jsonrpc': '2.0',
    'result': {'account': 'discordia',
    'follower_count': 2283,
    'following_count': 13}},
    {'error': {'code': -32602,
    'data': 'invalid account char',
    'message': 'Invalid parameters'},
    'id': 1,
    'jsonrpc': '2.0'},
    {'error': {'code': -32602,
    'data': 'invalid account char',
    'message': 'Invalid parameters'},
    'id': 1,
    'jsonrpc': '2.0'},
    {'error': {'code': -32602,
    'data': 'invalid account char',
    'message': 'Invalid parameters'},
    'id': 1,
    'jsonrpc': '2.0'}
    ]

#my first thought was to use a set, rather than a list, but dicts are unhashables.
#maybe a frozendict? but not sure if they compare equal to normal dicts.  in any #case, you can eliminate more than one type of dict this way. 

unwanted = [{'error': {'code': -32602,
    'data': 'invalid account char',
    'message': 'Invalid parameters'},
    'id': 1,
    'jsonrpc': '2.0'}]

print(f"{len(li1)=}")

li2 = [v for v in li1 if not v in unwanted]

print(f"{len(li2)=}")

output:

len(li1)=8
len(li2)=5

If all you want to is to strip out any error entries, this one liner does it.

li3 = [v for v in li1 if not "error" in v]

output:

len(li3)=5