send() takes from 1 to 2 positional arguments but 3 were given (discord.py)

user_15431231 0
Viewed 1649

i am trying to make it say the name of the user that did ~milk, it only produces the error when you type in discord ~milk here is the code that produces the error:

async def on_message(message):
   if message.author == client.user:
       return
   if message.content.startswith('~milk'):
       await message.channel.send(message.author, 'is blessed by the Baltic Gods of Dairy')
discord.py discord python
3 Answers

channel.send() takes only one argument (and the implicit self which makes it appear like 2)

You can write it like this:

await message.channel.send(f'{message.author.mention} is blessed by ...')
user_63334440

You are trying to pass 3 arguments to the discord instead of 2. When you try concatenate strings while passing them as arguements, always use +. If you use a comma, it treats them as separate arguments and therefore gets 3 different parameters(self,author and your message) instead of 2(self and message).

async def on_message(message):
   if message.author == client.user:
       return
   if message.content.startswith('~milk'):
       await message.channel.send(message.author+ 'is blessed by the Baltic Gods of Dairy')
user_138589910

send() takes only 1 to 2 positional arguments meaning it could be either send() or send(something here), in your code you can use either f string or , concatenation of strings like :-

await message.channel.send(f"{message.author.display_name} is blessed by the Baltic Gods of Dairy.")

or

await message.channel.send(str(message.author.display_name)+"is blessed by Baltic gods of Dairy.")
user_154296690
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