everyone!
I have a simple txt file, with few number in a row (',' is separator)
"1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21"
and this code:
num=[]
f = open('sample.txt','r')
for i in f:
num.append(i.split(',')
print(num)
my goal is to get list of items:
['1','2','3','4','5','6','7','8','9','10','11','12','13','14','15','16','17','18','19','20','21']
but i get list i list with 1 item:
[['1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21']]
looking for help
If you only have one line in your file, you don't need to loop over lines. You can assign num directly:
with open('sample.txt','r') as f:
num = f.read().split(',')
This code will work even if you have multiple line to read
num=[]
f=open('input.txt')
for i in f:
for j in (i.split(',')):
num.append(j.replace('\n',''))
print(num)
Explanation line by line steps
1.creating empty list
2.opening file
3.Taking one element from f at a time
4.splitting i which returns list and than taking one item from list as j
5.appending j and if there is newline character in j, than remove \n (this happens when we have to read more than on line)
Use extend, instead of append. What is the difference between Python's list methods append and extend?
num=[]
f = open('sample.txt','r')
for i in f:
num.extend(i.split(','))
print(num)