I write simple code in Wolfram Mathematica:
x = 2
k = 0
n = 15
total = Sum[((-1^k)*(x^(4*k + 1))) / (((2*k)!) * (4*k + 1)), k, n]
I want print result (the sum all members) and print all(!!!) intermediate results function Sum. How this make?
Print intermediate result Sum function
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2 Answers
Try
x=2;k=0;n=15;
Table[((-1^k)*(x^(4*k+1)))/(((2*k)!)*(4*k+1)),{k,n}]
That gives you a list of 15 elements.
Notice that I changed k,n to {k,n}.
Then Total[%] will add those to create a sum.
Your syntax is calculating a multiple indefinite sum, e.g.
Sum[Defer[g + h], g, h]
https://en.wikipedia.org/wiki/Indefinite_sum
If you add brackets around k, n you will obtain the sum Bill's answer shows.
total = Sum[((-1^k)*(x^(4*k + 1)))/(((2*k)!)*(4*k + 1)), {k, n}]
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