How to generate dictionaries from multiple lists?

user_5709240 0
Viewed 61

I have the following lists :

valuevalues = [4, 5, 35, 23, 16, 7, 12]
labelvalues = ['john', 'joe', 'Pier', 'Paul', 'Moe', 'Jane', 'Ruth']
labels = ['label' for i in range(len(valuevalues))]
values = ['value' for i in range(len(valuevalues))]

And I would like to generate the following dictionaries:

[{'label': 'john', 'value':4},
 {'label': 'joe', 'value':5},
 {'label': 'Pier', 'value':35},
 ...
 {'label': 'Ruth', 'value':12}]

Which kind of loop or function Should I use?

dictionary-comprehension list-comprehension python-3.x list python
5 Answers

Use zip and the following comprehension:

[{"label": l, "value": v} for l, v in zip(labelvalues, valuevalues)]
# [{'label': 'john', 'value': 4}, {'label': 'joe', 'value': 5}, 
#  {'label': 'Pier', 'value': 35}, {'label': 'Paul', 'value': 23}, 
#  {'label': 'Moe', 'value': 16}, {'label': 'Jane', 'value': 7}, 
#  {'label': 'Ruth', 'value': 12}]
user_23901820

Try this solution:

[{labels[i]:labelvalues[i],values[i]:valuevalues[i]} for i in range(len(valuevalues))]
user_84777380

It's generally considered to be a good thing to post your attempt first.

Anyway, what you are looking for is:

result = [{'label': label, 'value': value} for label, value in zip(labelvalues, valuevalues)]
user_73420790

Try this

a = [4, 5, 35, 23, 16, 7, 12]
b = ['john', 'joe', 'Pier', 'Paul', 'Moe', 'Jane', 'Ruth']
c = []

for x,y in zip(a, b):
    m = {'label':y, 'value':x}
    c.append(m)
print(c)

Output:

[{'label': 'john', 'value': 4}, {'label': 'joe', 'value': 5}, {'label': 'Pier', 'value': 35}, {'label': 'Paul', 'value': 23}, {'label': 'Moe', 'value': 16}, {'label': 'Jane', 'value': 7}, {'label': 'Ruth', 'value': 12}]
user_120632530 
listofdicts = [{'label':j,'value':i} for i,j in zip(valuevalues,labelvalues)]

The labels and values list is redundant.

user_126781900
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