I installed Julia to call from Python (Anaconda). When I try to call PyJulia, I get this error and I am not sure how to fix it:
Python 3.8.3 (default, Jul 2 2020, 17:30:36) [MSC v.1916 64 bit (AMD64)] :: Anaconda, Inc. on win32
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>>> from julia.api import Julia
>>> jl = Julia(compiled_modules=False)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "C:\Users\Andrea\AppData\Roaming\Python\Python38\site-packages\julia\core.py", line 468, in __init__
jlinfo = JuliaInfo.load(runtime)
File "C:\Users\Andrea\AppData\Roaming\Python\Python38\site-packages\julia\juliainfo.py", line 68, in load
proc = subprocess.Popen(
File "C:\Users\Andrea\anaconda3\lib\subprocess.py", line 854, in __init__
self._execute_child(args, executable, preexec_fn, close_fds,
File "C:\Users\Andrea\anaconda3\lib\subprocess.py", line 1307, in _execute_child
hp, ht, pid, tid = _winapi.CreateProcess(executable, args,
FileNotFoundError: [WinError 2] The system cannot find the file specified