I want to remove the all string after last underscore from the dataframe. If I my data in dataframe looks like.
AA_XX,
AAA_BB_XX,
AA_BB_XYX,
AA_A_B_YXX
I would like to get this result
AA,
AAA_BB,
AA_BB,
AA_A_B
I want to remove the all string after last underscore from the dataframe. If I my data in dataframe looks like.
AA_XX,
AAA_BB_XX,
AA_BB_XYX,
AA_A_B_YXX
I would like to get this result
AA,
AAA_BB,
AA_BB,
AA_A_B
You can do this simply using Series.str.split and Series.str.join:
In [2381]: df
Out[2381]:
col1
0 AA_XX
1 AAA_BB_XX
2 AA_BB_XYX
3 AA_A_B_YXX
In [2386]: df['col1'] = df['col1'].str.split('_').str[:-1].str.join('_')
In [2387]: df
Out[2387]:
col1
0 AA
1 AAA_BB
2 AA_BB
3 AA_A_B
pd.DataFrame({'col': ['AA_XX', 'AAA_BB_XX', 'AA_BB_XYX', 'AA_A_B_YXX']})['col'].apply(lambda r: '_'.join(r.split('_')[:-1]))
Explaination:
df = pd.DataFrame({'col': ['AA_XX', 'AAA_BB_XX', 'AA_BB_XYX', 'AA_A_B_YXX']})
Creates
col
0 AA_XX
1 AAA_BB_XX
2 AA_BB_XYX
3 AA_A_B_YXX
Use apply in order to loop through the column you want to edit.
I broke the string at _ and then joined all parts leaving the last part at _
df['col'] = df['col'].apply(lambda r: '_'.join(r.split('_')[:-1]))
print(df)
Results:
col
0 AA
1 AAA_BB
2 AA_BB
3 AA_A_B
If your dataset contains values like AA (values without underscore).
Change the lambda like this
df = pd.DataFrame({'col': ['AA_XX', 'AAA_BB_XX', 'AA_BB_XYX', 'AA_A_B_YXX', 'AA']})
df['col'] = df['col'].apply(lambda r: '_'.join(r.split('_')[:-1]) if len(r.split('_')) > 1 else r)
print(df)
Here is another way of going about it.
import pandas as pd
data = {'s': ['AA_XX', 'AAA_BB_XX', 'AA_BB_XYX', 'AA_A_B_YXX']}
df = pd.DataFrame(data)
def cond1(s):
temp_s = s.split('_')
temp_len = len(temp_s)
if len(temp_s) == 1:
return temp_s
else:
return temp_s[:len(temp_s)-1]
df['result'] = df['s'].apply(cond1)