How to exclude a specific element in a dictionary?

user_14653800 0
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I want to work with a random name from my_dict , except for the name "name300000.&**" , I want to skip it and pass to another name when choice(my_dict.values()) = "name300000.&**". So I did the following, but I am looking for a better solution ?

from random import choice
my_dict = {1: "name1", 2: "name2", 3:"name300000.&**", 4:"name4"}
if "name3" in choice(my_dict.values()):
    pass
name = choice(my_dict.values())
python-2.7 python
3 Answers

You can simply do

name = choice(tuple(set(my_dict.values()) - {"name300000.&**"}))
user_21663370

This is a possible solution:

from random import choice
my_dict = {1: "name1", 2: "name2", 3:"name300000.&**", 4:"name4"}

name = choice(list(my_dict.values()))
while name == "name300000.&**":
    name = choice(my_dict.values())

print(name)

Or, another possible solution is:

from random import choice
my_dict = {1: "name1", 2: "name2", 3:"name300000.&**", 4:"name4"}


while True:
    name = choice(list(my_dict.values()))
    if name != "name300000.&**":
        break

print(name)

The point is that you have to emulate a do while loop to correctly solve this problem, and in python, since it is not natively present, you can write in these ways.

user_137754830

You can simply use set difference function to remove unwanted values:

from random import choice
my_dict = {1: "name1", 2: "name2", 3:"name300000.&**", 4:"name4"}
name = choice(list(set(my_dict.values()).difference({"name300000.&**"})))
user_54307480
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