Return maximum value from list of tuples

user_2443822 0
Viewed 900

If I have the following nested list in parenthesis:

[('Frank', '8'), ('Peter', '10'), ('Spank', '0')]

What can I do to return the maximum value and corresponding name from the list?

Desired output:

('Peter', '10')

I have tried max(list, key=itemgetter(1))[0] with no luck.

tuples list nested python
3 Answers

Just convert the key field to int

data = [('Frank', '8'), ('Peter', '10'), ('Spank', '0')]
mx = max(data, key=lambda e: int(e[1]))
print(mx)

output

('Peter', '10')
user_4150160

Try with this function. It takes as input a list with the same format than in your example and returns the element with the greatest number.

def findMax (names): #names = [('Frank', '8'), ('Peter', '10'), ('Spank', '0')]
numbers = [] #list for storing the numbers
for i in names:
    numbers.append (int (i [1]))

return names [numbers.index (max (numbers))] #search the max value in numbers and print the names element with the same index
user_137588000

If you want to use operator.itemgetter, you should probably convert the second item of each tuple to int:

>>> from operator import itemgetter
>>> lst = [('Frank', '8'), ('Peter', '10'), ('Spank', '0')]
>>> max(((k, int(v)) for k, v in lst), key=itemgetter(1))
('Peter', 10)

Strings do lexographical ordering for comparisons by default, so doing the int conversion is necessary in this case. You can test this out by doing '8' > '10' and seeing that it gives back True. You can read the docs for more information.

user_52389150
Related