I would like to sort the below list of full names by their surname (a-z). How could we do that with a sorted function and a lambda? Is there a better way?
people = ['Fred Johnson', 'Tom E. Roth', 'Jazz Ishingham', 'Fred Kazai', 'Robert Wass', 'You Mee']
I would like to supplement the other answers: in the case when 'people' list elements can have trailing spaces, we can remove them this way:
sorted(people, key=lambda el: el.rstrip().split(' ')[-1])
Also we could use re module this way:
import re
sorter = lambda el: re.search(r'(\w+)(?:\s*)$', el).group(1)
sorted(people, key=sorter)
Here we take only a surname, without any trailing spaces.
From: https://chrisalbon.com/python/basics/sort_a_list_by_last_name/
The answer is to your problem is sorted(people, key=lambda x: x.split(" ")[-1]