Initializer is inaccessible due to 'internal ' protection level

user_125440 0
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I have a struct defined in Swift with public properties

public struct MyStruct {
   
    public let prop1: String
    public let prop2: String
}

In my code, I try to initialize the struct by doing

MyStruct(prop1: "abc", prop2: "def")

But I get complier error saying 'MyStruct initializer is inaccessible due to 'internal protection' level.

The struct and member are in public protection level. So I don't understand what is 'internal' protection level.

swift
1 Answers

First there are five different protection levels: private, fileprivate, internal, public and open.

Any property, func or your initialiser you declare without a protection level keyword will automatically declared as internal.

Internal means, that your property, method or initialiser is accessible everywhere within the same module.

It seems like you are trying to create a new struct out of another module. Best solution would probably be to create your own init instead of the automatically generated one and declare it also as public.

Hope this helps you.

user_133457440
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