How can I remove even numbers from an array?

user_11551360 0
Viewed 2367

I need to remove the even numbers for this array

function removeEvens(numbers) {

}

/* Do not modify code below this line */

const oddNumbers = removeEvens([1, 2, 3, 4, 5]);
console.log(oddNumbers, `<-- should equal [1, 3, 5]`);
arrays javascript
3 Answers

The first step is how you check for evens - you can do this using the modulus operator (%) to see if the remainder when divided by 2 is 0, meaning that the number is even. Next you can filter the array to include only the numbers which pass this test:

function removeEvens(numbers) {
    return numbers.filter(n => n % 2 !== 0); // if a number is even, remove it
}

const oddNumbers = removeEvens([1, 2, 3, 4, 5]);
console.log(oddNumbers);

user_38348410

You can use .filter to do this with one line.

function removeEvens(numbers) {
    return numbers.filter(n => n % 2 !== 0);
}


const oddNumbers = removeEvens([1, 2, 3, 4, 5]);
console.log(oddNumbers, '<-- should equal [1, 3, 5]');

user_66327440

Here is the code. Hope this will be helpful!

<!DOCTYPE html>
<html>
<head>
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
</head>
<body>
    <script>
        function removeEvens(numbers) {
            return numbers.filter(n => n % 2 == 1);
        }

        /* Do not modify code below this line */

        const oddNumbers = removeEvens([1, 2, 3, 4, 5]);
        console.log(oddNumbers);
    </script>
</body>
</html>
user_23878800
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