Conditional to compare three values

user_12060459 0
Viewed 244

I am trying to determine if there is a way for me to write an if statement that will result in true if three values are equal to each other.

EX:

if a == b == c
   puts "true"
end

Instead of having to write:

if a == b && a == c && b == c
if-statement ruby
3 Answers

You don't need all 3, if a equal b and c equal b it implies a equal c.

If you need it more scalable 3+ arguments, you can do:

Set[a, b, c].size == 1

Original answer was:

Set[a, b, c].one?

But it one? does not count nil or false elements. So Set[nil, nil].one? will be false.

Thanks to Sagar Pandya for pointing it out in the comments.

user_8616480

What about this? 

  [a, b, c].uniq.size == 1
user_55885060

As @Bodacious mentioned a == b && b == c would work due to the transitive property.

But if you have many items, you could do something like:

values = [a, b, c]
if values.all? { |value| value == value[0] }
  puts "true"
end

The all? method returns true if a block returns true for every item. So in that block, check to see if every item is equal to the first item.

Squeegy_620760
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