I have a list like this:
car_cost = [[carA, 10000], [carB, 20000], [carC, 30000]]
how can I effectively find the element that has the maximum second element?
in this case should be getting a index 2, or the element
[carC, 30000]
I can find the max second element value by
max(car_cost, key = lambda x:x[1])
But I don't know how to do the rest effectively, please show me how can I do this
Thank you very much!!!
max(car_cost, key = lambda x:x[1]) return a list with the car and the number. You can get it with index 0
item = max(car_cost, key=lambda x: x[1])
print(item[0]) # carC
@Guy has the simplest answer, but you can also do:
print(next(iter(max(car_cost, key=lambda x: x[1]))))
Or one-liner version of @Guy's solution:
print(max(car_cost, key=lambda x: x[1])[0])
following the logic you propose, this would be a possible solution.
We get the maximum element in a copy list, and we delete it and again we look for the maximum. Obviously this is not the most profitable but serves to get out of the way.
I recommend you read the following article. It will help you understand the correct logic.
https://www.geeksforgeeks.org/python-program-to-find-second-largest-number-in-a-list/
And here is code:
carA = 1
carB = 2
carC = 3
car_cost = [[carA, 10000], [carB, 20000], [carC, 30000]]
copy = car_cost
copy.remove(max(car_cost, key = lambda x:x[1]))
print(max(copy, key = lambda x:x[1]))