Is there a way to get all keys of type union type of objects { a: ...} | { b: ...} ? One thing worth mention — this type is generated dynamically.
Spent a few hours but without any luck...
Get keys of union of objects in TypeScript
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1 Answers
Conditional types follow the distributive law.
Something along these lines (or at least a start)
type Keys<T> = T extends {[key: string]: any} ? keyof T : never
type Test = Keys<{a: string} | {b: number} | {c: object}>
//type Test = "a" | "b" | "c"
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