Trying to print multiple text in same line with append method but outputs are different

user_12212802 0
Viewed 181

Trying to print possible number combinations in single line as list but the list have wrong output. My output is like this:

[[1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1]]

When it should be like this:

[0, 0, 0]
[0, 0, 1]
[0, 1, 0]
[0, 1, 1]
[1, 0, 0]
[1, 0, 1]
[1, 1, 0]
[1, 1, 1]

My code is

if __name__ == '__main__':
    x = 1
    y = 1
    z = 1 
kordinat = ["x","y","z"]
result = []
for xx in range(x+1):
    kordinat[0] = xx
    for yy in range(y+1):
        kordinat[1] = yy
        for zz in range(z+1):
            kordinat[2]= zz
            print(kordinat)
            result.append(kordinat)
print(result)
python-3.x python
4 Answers

You should take itertools.product():

from itertools import product

result = list(product(range(2), repeat=3))
print(result)
# [(0, 0, 0), (0, 0, 1), (0, 1, 0), (0, 1, 1), (1, 0, 0), (1, 0, 1), (1, 1, 0), (1, 1, 1)]

EDIT: This does not explain, why you end up having a list full of [1, 1, 1] elements. The reason can be found here. Through all your iterations, you work with a list called koordinat. When you append this to your overall list result, you append a reference to the very same object all the time. So you will have a list full of references to the same list koordinat. So changing koordinat to [1, 1, 1] in the last iteration, will change all references in your result list to this value as well. This can best be seen, when you print result after each append()

user_71361950

change this line: 

result.append(kordinat)

to

result.append(kordinat.copy())

list is passed or assigned as reference so if you change the value it'll change everywhere.

user_76998590

To print elements of list in new line use pprint as below,

>>> from pprint import pprint as pp
>>> pp(result)
[[1, 1, 1],
 [1, 1, 1],
 [1, 1, 1],
 [1, 1, 1],
 [1, 1, 1],
 [1, 1, 1],
 [1, 1, 1],
 [1, 1, 1]]

Edit-1:

Assuming, you are trying to find the binary numbers of the sequence. In your example, it is from 0-7(1-byte or 8-bits).

Try this,

>>> result = [[int(j) for j in "{0:03b}".format(i)] for i in range(8)]
>>> pp(result)
[[0, 0, 0],
 [0, 0, 1],
 [0, 1, 0],
 [0, 1, 1],
 [1, 0, 0],
 [1, 0, 1],
 [1, 1, 0],
 [1, 1, 1]]
user_83537110

If you want all the possible combinations of 0,1 of size 3, use combinations from itertools and call it as combinations([0,1],3). This will give you all the possible combinations you are expecting

user_101278520
Related