IntelliJ + AWS Toolkit + Serverless App: "Must be able to locate the handler in the project in order to deploy to Lambda"

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I have created a new Serverless project in IntelliJ using a HelloWorld style template app. This app I managed to build, deploy and run remotely in my AWS account. I even managed to integrate it with API gateway to make it accessible through the internet.

As the project is setup, it has 1 Lambda function called HelloWorldFunction. Its handler is called "helloworld.App::handleRequest" and I can see the configuration for this in the template.yaml file.

Now I want to create another Lambda function in the same application project. So, in IntelliJ, I follow these steps:

  • AWS Explorer > Lambda
  • Right-click on Lambda
  • Click "Create new AWS Lambda ..."
  • enter a function name (e.g. MyNewLambdaFunction)
  • enter the runtime (Java 8) and the S3 bucket and the IAM role (all is fine)
  • then I need to enter the name of the "Handler", and this is where my problem starts

I have tried different names here, such as "MyNewHandler", or "helloworld.App::handleRequest" (clearly this wouldn't work because it's already in use by the HelloWorldFunction), "helloworld.App2::handleRequest", .... and so on.

Each time I try another name or way to define the Handler, I get this error message:

Must be able to locate the handler in the project in order to deploy to Lambda

Question:

Do I need to first configure the new Lambda function in the template.yaml file or what do I need to call the Handler so it will work?

I am sure this is just a noob-error but I have been Googling this and haven't found anyone who has run into the same problem. I also read up on AWS on handlers but it only describes it at a conceptual level and not in practice where there are multiple Lambdas.

thanks for any help!

Andy

aws-serverless aws-lambda intellij-idea
4 Answers

I've had the same issues using pyCharm for Python.

I was able to solve it by using <file name without extension>.<function name> so my file is app.py and the function is lambda_handler so my handler was app.hello_world

It should be noted this is the same as what you see in the "Handler" field when using the AWS web management page.

user_18930820

My understanding is that you would need to add app2 class to the same package first:

click on the package name → new → Java Class → type app2

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Navigate to the implementation of the App2 class and click on the lambda icon in the gutter. You will notice that "Create New AWS Lambda" is added to the dropdown:

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When you select it, you will see that "Handler:" field has already been prepopulated correctly:

enter image description here

my understanding is that each handler must be placed in a separate class and the name of the handler handleRequest is standard and provided by the framework

user_15186850

Thius is how it looks in pycharm:

handler name in pycharm

user_60585160

I got the same issue but solved in a different way;

  • Quit WebStorm
  • Delete ".aws-sam" and ".idea" folders
  • Open the project again.

"Update function code" run without "Must be able to locate the handler in the project in order to deploy to Lambda"

user_57030320
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