How get result from php the same on java?

user_11265171 0
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Why on php this printf((2376995291 - 141 * 16777216) / 65535) on

result 174.0724040589.

On Java System.out.println((2376995291L - 141 * 16777216) / 65535)

result 65711 .

Why its two different result and how get result PHP on Java , i need get 174 on java.

php java
5 Answers
System.out.println((2376995291L - 141L * 16777216L) / (double)65535);

141 * 16777216 will technically overflow since it's greater than 2^31 - 1. So, make them as long numbers to avoid overflow and you could typecast the denominator if you like to get the result with decimal points as well.

user_49648220

In java Try this

System.out.println((2376995291L - 141 * 16777216L) / 65535L);
user_117013100

You need to cast the number to float or Java will simply ignore the decimal places.

System.out.println(((float) (2376995291L - 141L * 16777216L)) / 65535f)
user_54461970

Because multiplication of is long number.Need to define it as long

Splited into 2 step for just clarification.

    public static void main(String[] args) {
            Long te = (141L * 16777216L);
            System.out.println((2376995291L - te) / 65535);

        }
user_88183530

141 * 16777216 is too big for an int. If you do that part of the calculation as a long, you'll get the right answer.

jshell> (2376995291L - 141 * 16777216L) / 65535
==> 174
user_38906320
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