How to print std::map<int, std::vector<int>>?

user_6807211 0
Viewed 425

Following is my code for creating a map<int, vector<int>> and printing:

//map<int, vector>
map<int, vector<int>> int_vector;
vector<int> vec;
vec.push_back(2);
vec.push_back(5);
vec.push_back(7);

int_vector.insert(make_pair(1, vec));

vec.clear();
if (!vec.empty())
{
    cout << "error:";
    return -1;
}
vec.push_back(1);
vec.push_back(3);
vec.push_back(6);
int_vector.insert(make_pair(2, vec));

//print the map
map<int, vector<int>>::iterator itr;
cout << "\n The map int_vector is: \n";
for (itr2 = int_vector.begin(); itr != int_vector.end(); ++itr)
{
    cout << "\t " << itr->first << "\t" << itr->second << "\n";
}
cout << endl;

The printing part does not work because of the 

error: C2678: binary '<<': no operator found which takes a left-hand operand of type 
'std::basic_ostream<char,std::char_traits<char>>' (or there is no acceptable conversion)
c++17 stdmap stdvector iterator c++
2 Answers

The value of your maps(std::map<int, std::vector<int>>) is a vector of int s and there is no operator<< defined for printing a std::vector<int> in the standard. You need to iterate through the vector(i.e. values of the map) to print the elements.

for (itr = int_vector.begin(); itr != int_vector.end(); ++itr)
//     ^^ --> also you had a typo here: itr not itr2     
{
    cout << "\t " << itr->first << "\t";
    for(const auto element: itr->second) std::cout << element << " ";
    std::cout << '\n';
}

That being said, if you have access to C++11, you could use range-based for loops. And in C++17, you could do more intuitively structured binding declarations for the key-value of the map:

for (auto const& [key, Vec] : int_vector)
{
    std::cout << "\t " << key << "\t";                         // print key
    for (const auto element : Vec) std::cout << element << " ";// print value
    std::cout << '\n';

}

Remark: As @Jarod42 pointed out in the comments, the given code could be simplified if the entries are known beforehand.

for example with std::map::emplaceing:

using ValueType = std::vector<int>;
std::map<int, ValueType> int_vector;
int_vector.emplace(1, ValueType{ 2, 5, 7 });
int_vector.emplace(2, ValueType{ 1, 3, 6 });

or simply initialize the map using the std::initializer_list constructor of the std::map.

const std::map<int, std::vector<int>> int_vector { {1, {2, 5, 7}}, {2, {1, 3, 6}} };
user_96098400

error: C2678: binary '<<': no operator found

Also means you can write your own operator. Doing so can be handy as your objects become more complicated.

#include <iostream>
#include <vector>
#include <map>

using vector_int_type = std::vector<int>;

std::ostream& operator << (std::ostream& os, const vector_int_type& vect) {
    for (const auto& i : vect)
        os << '\t' << i;
    return os;
}

int main()
{
    std::map<int, vector_int_type> int_map;
    int_map[1] = vector_int_type{ 1,2,3 };
    int_map[2] = vector_int_type{ 4,5,6 };

    for (auto& item : int_map)
        std::cout << item.first << " is: " << item.second << std::endl;
}
user_31664760
Related