Distance between point to list of points

You are accidentally using indexing on your data even though you already separated your points into x, y. In addition, you are overwriting your list and not saving the data. Also the distance formula is incorrect it should be a subtraction between points not addition. Try this:

import math
s= [(1,4),(4,2),(6,3)]
p= (3,7)

p0,p1=p
dist=[]

for s0,s1 in s:
    dist_=math.sqrt((p0 - s0)**2 + (p1 - s1)**2) #Edit this line to [0]s and [1]s
    dist_= dist_+1 #Also change name and/or delete
#    print(dist)
    dist.append(dist_) #Save data to list

dist=math.sqrt((p0[0] - p1[0])**2 + (s0[1] - s1[1])**2)

Here, you are indexing integer.

Moreover, you've made mistake in calculation. It should be:

dist=math.sqrt((p0 - s0)**2 + (p1 - s1)**2)

If what is desired is a list of the distances, that can be done in a single line of code with a list comprehension:

import math
import pprint

s = [(1,2),(3,4),(-1,1),(6,-7),(0, 6),(-5,-8),(-1,-1),(6,0),(1,-1)]
p = (3,-4)

dists = [math.sqrt((p[0]-s0)**2 + (p[1]-s1)**2) for s0, s1 in s]

pprint.pprint(dists)

The other thing here is that I've removed the dist = dist + 1 from the OPs code. I don't see that being correct...why add 1 to each computed distance?

Result:

[6.324555320336759,
 8.0,
 6.4031242374328485,
 4.242640687119285,
 10.44030650891055,
 8.94427190999916,
 5.0,
 5.0,
 3.605551275463989]

Maybe try to change this line:

    dist=math.sqrt((p0[0] - p1[0])**2 + (s0[1] - s1[1])**2)

To:

    dist=math.sqrt((p0 - p1)**2 + (s0 - s1)**2)

If you would like the Euclidean distance, you could do something like this (even without import math)

s = [(1, 4), (4, 2), (6, 3)]
p = (3, 7)

for point in s:
    sum_ = sum((p[i] - point[i]) ** 2 for i in range(len(p)))
    distance = sum_ ** (1 / 2)  # take the square root, the same thing as math.sqrt()
    print(p, point, round(distance, 1))

Results:

(3, 7) (1, 4) 3.6
(3, 7) (4, 2) 5.1
(3, 7) (6, 3) 5.0

The error you get in your code is because you used indexing on an integer. Just like doing this:

>>> a = 3
>>> a[0]
Traceback (most recent call last):
  File "<input>", line 1, in <module>
    a[0]
TypeError: 'int' object is not subscriptable

In case you are not constrained by the packages you can use. An implementation using NumPy would be more swift.

import numpy as np

s = np.array([(1,4),(4,2),(6,3)])
p = np.array((3,7))

dist = np.linalg.norm(p - s, axis=1)

Result:

array([3.60555128, 5.09901951, 5.])