Remove specific words by comparing two lists

user_10835923 0
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I have two lists.

x=['billed_qty','billed_amt','sale_value']

y=['george billed_qty', 'sam billed_amt', 'ricky sale_value', 'donald billed_qty']

I need to eliminate the words in list y that occur in list x and want the resultant list as:

z=['george','sam','ricky','donald']

How can I achieve this?

Thanks

list python
6 Answers

Use regex with list comprehension:

comp = re.compile('|'.join(x))
z = [re.sub(comp, '', i).strip() for i in y]

print(z)
['george','sam','ricky','donald']
user_83208610

Use str.join with str.split in list comprehension:

z = [' '.join(w for w in s.split() if w not in x) for s in y]
print(z)

Output:

['george', 'sam', 'ricky', 'donald']
user_70937410

Why not:

print([' '.join(set(i.split()).difference(set(x))) for i in y])

Output:

['george', 'sam', 'ricky', 'donald']
user_87083640

I don't know if it covers all your cases, but a simple solution would be this:

for i in x:
  for idx, k in enumerate(y):
    y[idx] = k.replace(" "+i, "")

For every value in array x replace its value in array y with an empty string (including the space on the left).

user_17987070

At the first, split elements of y:

for i in range(0,len(y)):
    y[i] = y[i].split(' ')

So, y is:

[['george', 'billed_qty'], ['sam', 'billed_amt'], ['ricky', 'sale_value'], ['donald', 'billed_qty']]

Now, check existence of elements of x in y:

for i in range(0,len(y)):
    for j in range(0,len(x)):
        if x[j] in y[i][1]:
            y[i] = y[i][0]

y changes into:

['george', 'sam', 'ricky', 'donald']
user_84614930

For that you can solve it by using itertools.

Solution is as follow..

import itertools

z = [i.split() for i in y]

# This gives us z = [['george', 'billed_qty'], ['sam', 'billed_amt'], ['ricky', 'sale_value'], ['donald', 'billed_qty']]

w = list(itertools.chain.from_iterable(z))

# This gives us w = ['george', 'billed_qty', 'sam', 'billed_amt', 'ricky', 'sale_value', 'donald', 'billed_qty']

output = [a for a in w if a not in x]

# This gives us output = ['george', 'sam', 'ricky', 'donald']
user_78467000
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