I have this text like below:
아니다
bukan
싫다
tidak suka
훌륭하다
bagus
And I am trying to remove the English line(English Alphabets) and attach it to the end of upper line(Korean Alphabets) like this:
아니다bukan
싫다tidak suka
훌륭하다bagus
Now, Finally find almost close regular expression, which is this:
[가-힣]\R
However, It makes the text file like this:
아니bukan
싫tidak suka
훌륭하bagus
The problem is removing the one word of Korean too.
How can I solve this problem?
C++ std::regex does not support Unicode property classes like \p{Hangul}, but you may use the equivalent character class, [\u1100-\u11FF\u302E\u302F\u3131-\u318E\u3200-\u321E\u3260-\u327E\uA960-\uA97C\uAC00-\uD7A3\uD7B0-\uD7C6\uD7CB-\uD7FB\uFFA0-\uFFBE\uFFC2-\uFFC7\uFFCA-\uFFCF\uFFD2-\uFFD7\uFFDA-\uFFDC], see this reference.
Besides, \R is not supported either. You may probably just use \r?\n to match Windows/Linux style line endings, or (?:\r\n?|\n) to also support MacOS line endings.
Next, if you match and consume a Korean char, when replacing, you need to capture it into a capturing group and use a backreference to the group in the replacement pattern.
So, you may use
([\u1100-\u11FF\u302E\u302F\u3131-\u318E\u3200-\u321E\u3260-\u327E\uA960-\uA97C\uAC00-\uD7A3\uD7B0-\uD7C6\uD7CB-\uD7FB\uFFA0-\uFFBE\uFFC2-\uFFC7\uFFCA-\uFFCF\uFFD2-\uFFD7\uFFDA-\uFFDC])(?:\r\n?|\n)
Replace with $1 to put back the Korean char into the resulting string.
See the regex demo online.
The regex for the set of all Korean characters in unicode is this:
\p{Hangul}
There is more information here: https://www.regular-expressions.info/unicode.html
Maybe you also need a + after your group of characters?
Use the [\p{Hangul}]+\R regular expression instead of what you're using now.