type(of :) function compiler warning in Swift 4

user_8994745 0
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I have upgraded the project from Swift 3 to Swift 4, but the compiler suggested that the conditions in the if can not call value of non-function type 'AnyClass' (aka 'AnyObject.Type'). How to solve this?

func getHandler(_ type:AnyClass) -> CSHandler? {
    for handler in handlers {
        if type(of: handler) === type {
            return handler
        }

    }

    return nil
}
swift
1 Answers

I think compiler is getting confused with the parameter type and method type(of:) both have the same initial token. Can you change the parameter name from type to pType as below

func getHandler(_ pType: AnyClass) -> AnyObject? {
  for handler in handlers {
    if type(of: handler) === pType {
      return handler
    }
  }
  return nil
}

This should work for you and I would suggest you to file a bug report to apple regarding this issue

user_4687240
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