How to access named url arguments in permissions with Django REST Framework?

Question

I have an url config like

url(r'^user/(?P[0-9]+)/$', UserView.as_view())

And a view class like

class UserView(GenericAPIView):
    serializer_class = UserSerializer
    permission_classes = [MyCustomPermission]

    def get(self, request, id):
        # code...

The permission is like

class MyCustomPermission(BasePermission):
    def has_permission(self, request, view, *args, **kwargs):
    # code

How do I access id in MyCustomPermission? I can't find it from the request or from *args or *kwargs. Documentation doesn't say anything about this. I've tried to look the source code but can't find how to access those named url arguments. Is it even possible?

user_2089929 · Answer

you can access from the view.kwargs.

user_104349 · Answer

This is the wrong approach. Rather than trying to access keyword arguments there, you should be using object-level permissions and checking has_object_permission in your permission class.

user_9245907 · Answer

You can find them in:

request.resolver_match.kwargs.get('attribute_name')

How to access named url arguments in permissions with Django REST Framework?

3 Answers