Is there any way (without saving a file to disk and then deleting it) to convert a PIL Image object to a File object?
2 Answers
Let's look at what a file object is.
with open('test.txt', 'r') as fp:
print(fp)
# <_io.TextIOWrapper name='test.txt' mode='r' encoding='UTF-8'>
https://docs.python.org/3/library/io.html has more on the subject as well.
I suspect that for your purposes, it would be enough to have a BytesIO object.
import io
from PIL import Image
im = Image.new("RGB", (100, 100))
b = io.BytesIO()
im.save(b, "JPEG")
b.seek(0)
But if you really want the same object, then -
fp = io.TextIOWrapper(b)
Use a temporary file from the tempfile standard library.
from tempfile import TemporaryFile
from PIL import Image
fp = TemporaryFile()
img = Image.new("RGB", (100, 100))
img.save(fp, "PNG")
Don't forget to reset the position!
fp.seek(0)
Closing the file will remove it
fp.close()
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