example:
var s1 = Observable.of([1, 2, 3]);
var s2 = Observable.of([4, 5, 6]);
s1.merge(s2).subscribe(val => {
console.log(val);
})
I want to get [1,2,3,4,5,6]
instead of
[1,2,3]
[4,5,6]
example:
var s1 = Observable.of([1, 2, 3]);
var s2 = Observable.of([4, 5, 6]);
s1.merge(s2).subscribe(val => {
console.log(val);
})
I want to get [1,2,3,4,5,6]
instead of
[1,2,3]
[4,5,6]
My take is zip and map with Array.prototype.concat():
https://stackblitz.com/edit/rxjs-pkt9wv?embed=1&file=index.ts
import { zip, of } from 'rxjs';
import { map } from 'rxjs/operators';
const s1$ = of([1, 2, 3]);
const s2$ = of([4, 5, 6]);
const s3$ = of([7, 8, 9]);
...
zip(s1$, s2$, s3$, ...)
.pipe(
map(res => [].concat(...res)),
map(res => res.sort())
)
.subscribe(res => console.log(res));
The accepted answer from @maxime1992 will now cause deprecation warnings with the current version of RXJS. Here's an updated version:
import { forkJoin, of } from 'rxjs';
import { map } from 'rxjs/operators';
const s1$ = of([1, 2, 3]);
const s2$ = of([4, 5, 6]);
Observable
.forkJoin([s1$, s2$])
.pipe(
.map(([s1, s2]) => [...s1, ...s2])
)
.do(console.log)
.subscribe();